2y^2+8y=384

Solution for 2y^2+8y=384 equation:

2y^2+8y=384

We move all terms to the left:

2y^2+8y-(384)=0

a = 2; b = 8; c = -384;
Δ = b2-4ac
Δ = 82-4·2·(-384)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-56}{2*2}=\frac{-64}{4}
=-16
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+56}{2*2}=\frac{48}{4}
=12
$